2y^2+2y+27=0

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Solution for 2y^2+2y+27=0 equation: 



2y^2+2y+27=0

a = 2; b = 2; c = +27;
Δ = b2-4ac
Δ = 22-4·2·27
Δ = -212
Delta is less than zero, so there is no solution for the equation

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